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Question : 32 of 160
Marks:
+1,
-0
Solution:
Given,
|b|=‌|a| and
|c|=‌|a| and
‌‌a⋅b=b⋅c=a⋅c=0 |a+b+c|2=|a|2+|b|2+|c|2=4|b|2+|b|2+3|b|2=8|b|2 ⇒|a+b+c|=2√2|b| Angle between
(a+b+c) and
b is
cos‌θ‌‌=‌⇒cos‌θ=‌=‌ θ=‌‌cos−1(‌)
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