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Question : 31 of 160
Marks:
+1,
-0
Solution:
Given,
|b|=2|a| and
|c|=3|a| Angle between each pair of vector is
π∕3.
|a+b+c|2=|a|2+|b|2+|c|2+2|a||b|cos‌π∕3 +2|b|c|cos‌+2|a|c|cos‌25=|a|2+4|a|2+9|a|2+4|a|2×‌+2×6|a|2×‌+6|a|2×‌ 25=25|a|2⇒‌‌|a|=1 ∴‌‌|b|=2⇒|c|=3⇒|a|+|b|+|c|=1+2+3=6
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