TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

Given that, initial velocity, u=5m/s and horizontal range =2× greatest height attained
or ⇒‌‌‌

sin‌θ

2

=2‌cos‌θ⇒‌

sin‌θ

cos‌θ

=4
If we form a right angled triangle, with these sides, then Now, sin‌θ=‌

4

√17

and cos‌θ=‌

1

√17

So, the horizontal range
R=‌

u2‌sin‌2‌θ

g

=‌

u2×2‌sin‌θ‌cos‌θ

g

=117m=2m