TS EAMCET 14-Sep-2020 Shift 1 Solved Paper

When a particle moves along a vertical circle, then it has its minimum speed at the highest point of the vertical circle and in this case it just completes the loop. The minimum speed is
vmin=√gR⇒vmin∝√R
So, ⇒‌‌‌

v

(vmin)2

=‌

1

√2

⇒(vmin)2=√2v