TS EAMCET 06 May 2019 Shift 1 Solved Paper

Section: Mathematics

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Question : 21 of 160

Marks: +1, -0

If cot θ + tan θ = 3 and 1 - cos2 θ - α cos θ = 0 , then

6α2(9−α2) = 1
6α2(α2−9) = 1
9α2(6−α2) = 1
9α2(α2−6) = 1

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