TS EAMCET 06 May 2019 Shift 1 Solved Paper

Section: Mathematics

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Question : 20 of 160

Marks: +1, -0

If sin 2θ and cos 2θ are solutions of x2 + bx - x = 0, then

b2 + 2c + 1 = 0
b2 + 2c - 1 = 0
b2 - 2c + 1 = 0
b2 - 2c - 1 = 0

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