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Question : 76 of 160
Marks:
+1,
-0
Solution:
Consider the integral
I‌‌=|x‌sin(πx)|dx ‌‌=x‌sin‌π‌x‌d‌x−x‌sin‌π‌x‌d‌x ‌‌=2‌x‌sin‌π‌x‌d‌x−x‌sin‌π‌x‌d‌x ‌‌=2[‌+sin‌]01−[‌+sin‌]13∕2 Solve further
I‌‌=2[‌+0−0]−[0−‌−‌] ‌‌=‌+‌
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