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Question : 75 of 160
Marks:
+1,
-0
Solution:
Consider the integral
I=‌‌sin(‌−x)‌d‌x Let
x=‌ dx=−‌dt At
x=‌ the value of
t is 3
At
x=3 the value of
t is
‌ Therefore,
I‌‌=t‌sin(t−‌)(‌)‌d‌t ‌‌=−1‌‌‌sin(t−‌)‌d‌t ‌‌=‌‌sin(‌−t)‌d‌t ‌‌=−‌‌sin(‌−t)‌d‌t So I‌‌=−I 2I‌‌=0 I‌‌=0
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