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Question : 34 of 160
Marks:
+1,
-0
Solution:
Consider the vectors,
a=2i−3j+k b=i−j+2k And
c=2i+j+k So
|(a×b)×c|‌‌=|(c⋅a)b−(c⋅b)a| ‌‌=|(2i−2j+4k)−(6i−9j+3k)| ‌‌=|−4i+7j+k| ‌‌=√66 And,
|a×(b×c)|=∣(a⋅c)b−(a⋅b)c =|(2i−2j+4k)−(14i+7j+7k)| =|−12i−9j−3k| =√234 Therefore,
‌=√‌ |(a×b)×c|=√‌|a×(b×c)|
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