© examsiri.com
Question : 33 of 160
Marks:
+1,
-0
Solution:
a=i+2j−k And
b=i+j+k ‌ So, ‌ a×b‌‌=|| ‌‌=3i−2j−k Therefore,
[a‌b‌p]‌‌=p⋅(a×b) ‌‌=p⋅(3i−2j−k) Also,
[a‌b‌p]=|P||a×b|cos‌θ since[a‌b‌p] is maximum Therefore,
p‌‌=‌ ‌‌=‌(3i−2j−k)
© examsiri.com
Go to Question: