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Question : 34 of 160
Marks:
+1,
-0
Solution:
The value of
θ is
r×a‌‌=b |r×a|‌‌=|b| r|a|sin‌θ‌‌=|b| sin‌θ‌‌=‌=‌ θ=60° Then
(r×a)×a‌‌=b×a (r⋅a)⋅a−|a|2r‌‌=b×a r‌‌=‌[(r⋅a)⋅a−b×a] ‌‌=‌[a−(b×a)]
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