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Question : 33 of 160
Marks:
+1,
-0
Solution:
The equation of the line is
r=i+j+t(2i−j+k) r=2i+j−k+s(3i−5j+2k) The general equation of line is
r=a+λb a2−a1=i−k and
b1×b2=|| =3i−j−7k The shortest distance can be calculated from the expression
=‌| (a2−a1)(b1×b2) |
| |b1×b2|‌ |
=‌| (i−k)⋅(3i−j−7k) |
| √59 |
=‌
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