Time and Work Practice Test 2 with solutions

Question : 22 of 40

Marks: +1, -0

A man, a woman and a boy can complete a job in 3, 4 and 12 days respectively. How many boys must assist one man and one woman to complete the job in

1/4

of a day?

Solution:

(one man + one woman)'s

1/4

day's work =

1/{3×4}+1/{4×4}

1/{12}+1/{16}

7/{48}

Remaining part of work = 1 -

7/{48}

{41}/{48}

, which will be done by boys alone in

1/4

day.
One boy's

1/4

day's work =

1/{4×12}

1/{48}

Hence, required number of boys =

{{41}/{48}}/{1/{48}}

= 41

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