Time and Work Practice Test 2 with solutions

Question : 21 of 40

Marks: +1, -0

10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?

225 days
200 days
150 days
125 days

Validate

Solution:

10 men's 6 days' work = 10 × 6 ×

1/{100}

3/5

Hence, 15 women's 6 days' work = 1 –

3/5

2/5

Then, 1 woman's 1 day's work =

2/5 × 1/{15×6}

1/{225}

Therefore, one woman alone will complete the work in 225 days.

Go to Question:

Prev Question

Next Question