If y=\log [\tan \sqrt{\frac{2^x-1}{2^x+1}}] , x>0, then (\frac{d y}{d x}) _{x=1}= [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : 4√3log29sin(2√3)

{4 \sqrt{2} \log 2}/{9 \sin ( {2}/{\sqrt{3}}) }

{4 \sqrt{3} \log 2}/{9 \sin ( {\sqrt{3}}/{2}) }

{4 \sqrt{3} \log 2}/{9 \sin ( {2}/{\sqrt{3}}) }

{4 \sqrt{2} \log 2}/{9 \sin ( {\sqrt{3}}/{2}) }

Differentiation

Section: Mathematics

Question : 8 of 15

Marks: +1, -0

If y=log[tan‌√‌

2x−1

2x+1

],x>0, then (‌

)x=1=

[TG EAPCET 10 May 2024 Shift 1]

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