If \log y=y^{\log x} then \frac{d y}{d x}= [TG EAPCET 10 May 2024 Shift 1]

Correct Answer is : y(logy)2x(1−logxlogy)

\frac{y(\log y)^2}{x(1-\log x \log y)}

\frac{x(\log x)^2}{y(1-\log x \log y)}

\frac{x(1-\log x \log y)}{y(\log y)^2}

\frac{y(1-\log x \log y)}{x(\log x)^2}

Differentiation

Section: Mathematics

Question : 7 of 15

Marks: +1, -0

If log‌y=ylog‌x then ‌

[TG EAPCET 10 May 2024 Shift 1]

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