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Question : 33 of 160
Marks:
+1,
-0
Solution:
‌‌ Given, ‌a=+2+2‌ and ‌b=2−+p‌∵a⋅b=|a||b|cos‌θ‌(2−2+2p)=√9√5+p2⋅cos‌60∘‌‌‌2p=3√5+p2‌‌⇒‌‌4p=3√5+p2‌⇒‌‌16p2=9(5+p2)‌⇒‌‌16p2=45+9p2‌⇒‌‌7p2=45⇒p2=‌‌⇒‌‌p=‌
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