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Question : 32 of 160
Marks:
+1,
-0
Solution:
Given,
a=+√11−2,
b=+√11−10∴ component of
b perpendicular to
a is
‌b−(a⋅b)‌=(+√11−10)‌−[‌⋅(+√11−10)]‌‌=+√11−10−‌⋅‌‌=+√11+√11−2)‌=−−2(+√11−2)‌=−(+√11−6+6)
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