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Question : 24 of 160
Marks:
+1,
-0
Solution:
‌16sin‌12∘‌cos‌18∘‌s‌i‌n‌48∘‌=16sin‌12∘sin‌72∘sin‌48∘‌=16sin‌12∘sin‌(60+12∘)sin‌(60∘−12∘)‌=‌sin‌3(12∘)=4sin‌36∘‌=‌=√10−2√5
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