TG EAMCET 2 May 2025 Shift 2 Paper

The force in SHM is F=−kx
The maximum force is Fmax=−kA
Given, F=0.866F‌max ‌
So,
−kx‌=0.866(−kA)
x‌=0.866A
The velocity in SHM is v=ω√(A2−x2)
‌v=ω√A2−(0.866A)2
‌v=ω√A2−0.75A2=ω√0.25A2
‌v=ω(0.5A)
The maximum velocity in SHM occurs at x=0, So vmax=ωA
The ratio is ‌

v

vmax

=‌

0.5ωA

ωA

‌

v

vmax

=0.5=‌

1

2

The ratio of its velocity at that point and its maximum velocity is ‌

1

2

.