TG EAMCET 2 May 2025 Shift 2 Paper

Moment of inertia of ring about its center:
ICM=MR2
Using the parallel axis theorem:
The parallel axis theorem says: If you know the moment of inertia of an object about its center ( ICM ), then the moment of inertia about a parallel axis a distance R away is:
I=ICM+MR2
For a thin circular ring, this axis through the edge is a distance R from the center, so:
I=MR2+MR2=2MR2
So, MR2=‌

I

2

Finding the moment of inertia about the diameter:
The moment of inertia of a ring about its diameter is:
Id=‌

MR2

2

Substituting from equation (i):
Replace MR2 with ‌

I

2

:Id=‌

‌ I 2

2

=‌

I

4