TG EAMCET 2 May 2025 Shift 1 Paper

Since, there are three Urn.
So, P(Urn‌A)=‌

1

3

=P(Urn‌B)=P(Urn‌C)
Now, probability of drawing a white ball from each Urn
Urn A 6 white balls, 2 black balls.
Total = 8 balls
P(‌ White ‌∕‌ Urn ‌A)=‌

6

8

=‌

3

4

Urn B 5 white balls, 3 black balls
Total = 8 balls
P(‌ White ‌∕‌ Urn B ‌)=‌

5

8

Urn C 4 white balls, 4 black balls
Total =8 balls
P(‌ White ‌∕‌ Urn C ‌)=‌

4

8

=‌

1

2

So, the total probability of drawing a white ball is
‌P(‌ White ‌)=P(‌ White ‌∕‌ Urn ‌A)⋅P(‌ Urn ‌A)
‌+P(‌ White ‌∕‌ Urn ‌B)⋅P(‌ Urn ‌B)
‌+P(‌ White ‌∕‌ Urn ‌C)⋅P(‌ Urn ‌C)
‌=‌

1

3

×‌

3

4

+‌

1

3

×‌

5

8

+‌

1

3

×‌

1

2

‌=‌

1

4

+‌

5

24

+‌

1

6

‌=‌

6+5+4

24

=‌

15

24

=‌

5

8