TG EAMCET 2 May 2025 Shift 1 Paper

Number of spade cards =13, number of kings =4
Prime numbered cards are 2,3,5 and 7
So, total primes cards = 4 suits ×4
numbers
⇒16 cards
But, a single card can be both a king and a spade or a prime and a spade.
So, the number of favourable outcomes.
Case I Spade that is not a king or prime =13−1−4=8
Case II King that is not a spade or prime = 3
Case III Prime card that is not a spade or king =16−4=12
So, total favourable cases
⇒‌‌8×3×12=288
and total number of ways to choose 3 cards from 52 cards =‌52C3
=‌

52!

3!49!

=‌

52×51×50

6

=22100
Thus, required probability
=‌

288

22100

=‌

72

5525