Symbiosis National Aptitude Test SNAP 2019 Paper

Total number of chocolates.
= 3 kitkat + 2 five stars + 3 Bar one
= 8
Number of way of selecting three chocolates out of 8 = $\stackrel{8}{}{\mathit{C}}_3$ = 56
Number of ways of selecting 3 chocolates out of 5 chocolates
(i.e. 2 Five star + 3 Bar one)
such that no kitkat chocolate being selected
$\stackrel{5}{}{\mathit{C}}_3$ = 10
Number of ways of selecting 3 chocolates such that atleast one of them is kitkat.
= 56 – 10 = 46