Symbiosis National Aptitude Test SNAP 2019 Paper

Let perimeter of Square = Perimeter of Circle = Perimeter of Hexagon = Perimeter of Octagon = 264 cm
Side of square = $\frac{264}{4}$ = 66 cm
Area of square = ${\left(66\right)}^2$ = 4356 $\mathit{c}{\mathit{m}}^2$
Radius of circle = $\frac{264\times 7}{2\times 22}$ = 42 cm
Area of circle = $\frac{22}{7}\times 42\times 42$ = 5544 $\mathit{c}{\mathit{m}}^2$
Side of hexagon = $\frac{264}{6}$ = 44 cm
Area of hexagon = 6 × $\frac{\sqrt{3}}{4}\times {\left(44\right)}^2$ = 5029.73 $\mathit{c}{\mathit{m}}^2$
Side of octagon = $\frac{264}{8}$ = 33 cm
and Area of octagon of side (a) = $2{\mathit{a}}^2\left(1+\sqrt{2}\right)$ here a = 33 cm
∴ Area = $2{\left(33\right)}^2\left(1+\sqrt{2}\right)$
= 2 × 1089(1 + 1.414)
= 5257.7 $\mathit{c}{\mathit{m}}^2$
Decreasing order of area are
Circle (5544) > Octagon (5257.7) > Hexagon (5029.73) > Square (4356)