SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 140 of 200

Marks: +1, -0

The total charge q(t), in the coulombs, that enters the terminal of an element is:

\q(t)= \{ \table0,, t<0;2t,,0≤t≤2;3+e^{-2(t-2)},,t>2

Determine the current at t = 5 s.

Solution:

t = 5 s so, equation 3rd is consider.

i ={ \dQ }/{ \dt }={ \d }/{ \dt }(3+ e ^{-2( t -2)})

i = e ^{-2( t -2)} { \d }/{ \dt }[-2( t -2)]

i = e ^{-2( t -2)}(-2)

i =-2 e ^{-2( t -2)}

Put the value of t = 5, then we get,

i=-2 e^{-6} \A

Go to Question:

Prev Question

Next Question