SSE JE Electrical Engineering 24 March 2021 Shift 2 Paper

Question : 139 of 200

Marks: +1, -0

Determine the average and effective values of the given waveform.

Solution:

\RMS \Value = \V _{ \RMS }=√{{1}/{ \T }∫↖{\T}↙{t=0}\V^2 \dt}

\V _{ \RMS }=√{{1}/{0.3}∫↖{t=0.1}↙{t=0}20^2\dt}

\V _{ \RMS }= √{400/0.3 [0.1-0]}

\V _{ \RMS }= √{400/0.3×0.1}

\V _{ \RMS }= √133.3\V

Average Value

=\V_\Avg=1/\T\;∫↖{t=\T}↙{t=0}\V_0\dt

\V_\Avg=1/0.3∫↖{t=0.1}↙{t=0}20\dt

\V_\Avg=20/0.3[0.1-0]

= 20/3 =6.67\V

Go to Question:

Prev Question

Next Question