SSC MTS Model Paper 5

Question : 27 of 148

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A person saw an eagle in east at an angle of elevation of 30°. In 24 seconds the eagle flew from east to west and then angle of elevation changed to 60°. If the eagle is flying at a height of 288 m, then find the speed of the eagle.

$8 √ { 3}$ m/sec
16 m/sec
$16√3$ m/sec
48 m/sec

Validate

Solution:

ATQ,

√{ 3}

= 288 m (given) and eagle flies for 24 seconds
∴ speed of eagle =

{ 288 × 4 } /{ \√ { 3 } × 24 }

16√3

m/sec.

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