SSC MTS Model Paper 4

Question : 28 of 150

Marks: +1, -0

It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

3 times
4 times
5 times
6 times

Validate

Solution:

Let the time taken by 3 men = x days
Time taken by 9 women = x + 5 days
3m = x day
2 m =

{3x}/2

days
Similarly, 9w = x + 5 days
3w = 3(x + 5) days
ATQ,

{ 2 }/ { 3 x } + { 1 } /{ 3 ( x + 5 ) } = { 1 } /{ 6 } { 2 x + 10 + x } /{ 3 x ( x + 5 ) } = { 1 } /{ 6 }

⇒ 18x + 60 = 3x2 + 15x ⇒ 3x2 − 3x − 60 = 0
Time taken by 1 man = 3x = 3 × 5 = 15 days
Time taken by 1 women = 9(x + 5) = 90 days
Required output = 6 times

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