If \cos ^ { 2 } \alpha + \cos ^ { 2 } \beta = 2then find the value of \tan ^ { 3 } \alpha + \sin ^ { 5 } \beta

SSC MTS Model Paper 2

Question : 38 of 150

Marks: +1, -0

\cos ^ { 2 } α + \cos ^ { 2 } β = 2

then find the value of

\tan ^ { 3 } α + \sin ^ { 5 } β

Solution:

(2)

\cos ^ { 2 } α + \cos ^ { 2 } β = 2

= 1 - \sin ^ { 2 } α + 1 - \sin ^ { 2 } β = 2

= \sin ^ { 2 } α + \sin ^ { 2 } β = 0

= \sin α = \sin β= 0

= α= α = 0

\tan ^ { 3 }α + \sin ^ { 5 }β = 0

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