SSC JE Mechanical Engineering 2018 Set 1 Paper

Question : 192 of 200

Marks: +1, -0

The pressure drop for a relatively low Reynolds number flow in a 600 mm, 30 m long pipeline is 70 kPa. What is the wall shear stress?

Solution:

Wall shear stress

τ=∂ p/∂ x.r/2

={70 ×10^3}/30×{300×10^{-3}}/2

= 350 Pa

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