SSC JE Mechanical Engineering 2017 Set 1 Paper

Question : 177 of 200

Marks: +1, -0

A solid shaft can resist a bending moment of 3 KNm and a twisting moment of 4 KNm together, then the maximum torque that can applied is ______.

Solution:

\T_\equivalent=√{M^2+T^2}

=√{3^2+4^2}=5\KNm

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