SSC JE Mechanical Engineering 2017 Set 1 Paper

Question : 176 of 200

Marks: +1, -0

The outside diameter of a hollow shaft is twice it's inside diameter. The ratio of its torque carrying capacity to that of a soild shaft of the same material and the same outside diameter is _____.

$15 /16$
$3 / 4$
$1 /2$
$1 /16$

Validate

Solution:

From torsion equation

(T/J) = ({Gθ}/L) = (τ/R)

The strength of a solid shaft in torsion is given by,

T_1

(solid shaft) =

(π/16)

× max stress ×

D^4

Solid shaft dia = D

T_2

(hollow shaft) =

(π/16)

× max stress ×

{(D^4-d^4)/D}

Hollow shaft diameters D = 2d

T_1/T_2 = 15/16

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