SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 117 of 200

Marks: +1, -0

Find H = ____ A/m at the center of a circular coil of diameter 1m and carrying a current of 2A.

Solution:

d = 1m
I = 2A
H = ?
Magnetic field intensity at center of a circular coil

H = I /{2πR} = 2/{ 2π×1/ 2 }= 0.636

Go to Question:

Prev Question

Next Question