SSC JE Electrical Engineering 26 Sep 2019 Shift 1 Paper

Question : 116 of 200

Marks: +1, -0

If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is:

Solution:

At full load loss

= I^2R

At half load loss

= (I/2)^2× R = 400

∴

I ^2/4×R= 400

∴ Full load loss

= I^2R = 400 × 4 = 1600 W

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