SSC JE Electrical Engineering 24 Jan 2018 Morning Paper

Question : 118 of 199

Marks: +1, -0

Determine the power dissipated (in W) by the 6 ohms resistor in the circuit given below.

Solution:

–6 + 10 I + 6 = 0
I = 0
∴ Power dissipated in 6 Ω resistor

= I^2R

= (0)^2 × 6= 0 W

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