SSC JE Electrical Engineering 24 Jan 2018 Morning Paper

Question : 107 of 199

Marks: +1, -0

What will be the value of capacitance (in micro–Farad) of a capacitor when the potential difference between the terminals of the capacitor is 40 V and the charge stored in the capacitor is 8 mC?

Validate

Solution:

Given data
V = 40 V
Q = 8 mc = 8 × 10

^{–3}

C
C = ?
Now Q = CV

⇒C=Q/V

={8×10^{-3}}/40=200\µf

Go to Question:

Prev Question

Next Question