SSC JE Electrical Engineering 23 Jan 2018 Morning Paper

Question : 110 of 200

Marks: +1, -0

Calculate the equivalent capacitance (in µF) between point A and B.

Solution:

{AC}/{AB}={BC}/{CD}

5/T=10/10

⇒ Given circuit is balanced wheat stone bridge
⇒ CD is removed
Now equivalent capacitance

C_\eq=10/3+10/3=23/3µf

= 6.7 µf

Go to Question:

Prev Question

Next Question