SSC JE Electrical Engineering 22 Jan 2018 Morning Paper

Question : 127 of 200

Marks: +1, -0

Determine the reluctance (in Amp-turn/wb) of a coil, when the flux through the coil is 25 Wb and the value of produced mmf is 50 Amp-turns.

Solution:

Given data,
ϕ = 25 Wb,
mmf = 50 A-turns
Now Reluctance is given by S

={NI}/ϕ=50/25

= 2 AT/Wb

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