SSC JE Electrical Engineering 22 Jan 2018 Morning Paper

Question : 126 of 200

Marks: +1, -0

What will be the produced mmf (in Amp-turns) in a coil, if the coil has 160 turns and carries a current of 0.15 A?

Solution:

Given data
N = 160 turns
I = 0.15 A
Now mmf (Ampere turns) = N × I = 160 × 0.15 (A turns)

=160×15/100

= 24 A-turns

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