SSC JE Electrical Engineering 22 Jan 2018 Morning Paper

Question : 121 of 200

Marks: +1, -0

Which of the following is the dimensional formula for mutual inductance?

Solution:

ωL = ML^2 T^{–3} A^{–2}

Now

ω = 2πf

dimension of

ω=1/T

∴ dimension of L

={ML^2T^{-3}A^{-2}}/{1/T}

= ML^2T^{–2}A^{–2 }

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