SSC JE Electrical Engineering 22 Jan 2018 Morning Paper

Question : 118 of 200

Marks: +1, -0

Determine the Norton’s resistance (in ohms) between terminals A and B for the circuit given below.

Solution:

In order to find the Norton Resistance, All voltage source is short circuited and all current source are open circuit i.e.

Redrawing above circuit we get

∴R_\AB=(9/5+3)Ω

=24/5Ω=4.8Ω

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