SSC JE Electrical Engineering 22 Jan 2018 Evening Paper

Question : 126 of 200

Marks: +1, -0

Determine the self–inductance (in mH) of a 4 m long air–cored solenoid, if the solenoid has a cross sectional area of 0.02 square meter and has 60 turns.

0.064
0.036
0.045
0.023

Validate

Solution:

Given data,
l = 4 m
A = 0.02 m

^{^2}

N = 60
self inductance is given by

L={µ_0µ_rN^2A}/\l

={4π×10^{-7}×60×60×0.02}/4

∴L=0.023\mH

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