SSC JE Electrical Engineering 22 Jan 2018 Evening Paper

Question : 125 of 200

Marks: +1, -0

Determine the magnitude of induced EMF (in V) in a coil, if the current changes from + 2 A to –2 A in 0.5 seconds and the coefficient of mutual induction is 0.5.

Validate

Solution:

Given data
M = 0.5
t = 0.5 sec
Now

{di}/{dt}={2-(-2)}/M=8A\/\sec

Now induced lmf

=M×{di}/{dt}

=0.5×8=4V

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