SSC JE Electrical Engineering 22 Jan 2018 Evening Paper

Question : 107 of 200

Marks: +1, -0

Determine the equivalent capacitance (in µF) of the given electrical network

Solution:

Here

C_1 , C_2

and

C_3

are connected in series

1/C_\eq=1/C_1+1/C_2+1/C_3

1/C_\eq=1/4+1/10+1/40

1/C_\eq=15/40

C_\eq=8/3\µ\f

Now 20 µf and

8/3

µf are connected in parallel

∴\C_{\AB}=(20+8/3)\µ\f

= 22.66 µf

Go to Question:

Prev Question

Next Question