SSC JE Electrical Engineering 2015 Paper

Question : 146 of 199

Marks: +1, -0

An alternator is supplying a load of 300 kw at a power factor of 0.6 lagging. If the power factor is raised to unity, how many more kw can alternator supply?

300 kw
100 kw
150 kw
200 kw

Validate

Solution:

\Power \factor= {\Active \Power}/{\Apparent \Power}

0.6=300/{\Apparent \Power}

Apparent Power =

300 /0.6=500

KvA
At using power factor, active Power
= Apparent Power = 500KvA.
So, ⇒500 – 300 = 200 Kv more KW Require.

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