SSC JE Electrical Engineering 2015 Paper

Question : 145 of 199

Marks: +1, -0

The unit for permeability is:

Solution:

\Reluctance (R)= {\Ampere \Turn}/ \Weber

R=1/{µA}

µ=1/{RA}

=\Weber/{\Ampere \Turn}× \Meter / {\Meter}^2

=\Weber/{\Ampere \Turn . \Meter}

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