SSC JE Electrical Engineering 2014 Set 1 Paper

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Question : 102 of 200

Marks: +1, -0

The R

_{\eq}

for the circuit shown in figure is

14.4 Ω
14.57 Ω
15.27 Ω
15.88 Ω

Solution:

[6Ω∥ 4Ω={6+4}/10=2.4Ω]

⇒

\Req = 4Ω+ 2.4Ω + 8Ω

= 14.4

Ω

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