SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 195 of 200

Marks: +1, -0

Calculate the area of field, when the initial reading = 9.918 and final reading = 4.254 were recorded by planimeter. Take, Multiplying constant of instrument (M) = 100

\cm^2

, Instrument constant (C) = 23.521 and Number of times the zero mark of the dial passes the fixed index mark of the instrument (N) = -1

655.7 $\cm^2$
895.7 $\cm^2$
785.7 $\cm^2$
986.5 $\cm^2$

Validate

Solution:

M = 100

\cm^2

C = 23.521
F = 4.254
I = 9.918
N = -1

​\Δ=\M(\F−\I±10\N+\C)​

Δ = 100 × (4.254 - 9.918 - 10 + 23.521)

= 785.7 \cm^2

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