SSC JE Civil Engineering 30-Oct-2020 Shift 2 Paper

Question : 194 of 200

Marks: +1, -0

According to IRC recommendations, what shall be the rounded off value of overtaking sight distance, on a two-lane highway for the case in which design speed = 50 km/h, time component for overtaking maneuver and for opposing vehicle are 10 seconds and 7 seconds, respectively?

470 m
235 m
165 m
340 m

Validate

Solution:

Distance while overtaking maneuver =

(50 × 5/18)

m/s × 10 sec = 138.88 m
Distance while crossing opposing vehicle =

(50 × 5/18)

m/s × 7 = 97.22 m
Overtaking sight distance = 138.88 + 97.22 = 236.1 m
The nearest answer is option 2, i.e 235 m

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